Question

The pollutant sulphur dioxide can removed from the air by reaction with calcium carbonate in the presence of oxygen. What mass of calcium carbonate is needed to remove 1 tonne of sulphur dioxide? 

2CaCO₃ + 2SO₂ + O₂ → 2CaSO₄ + 2CO₂

Answer 1

Molar mass of SO₂ = 64 .066g

Molar mas of CaCO₃ = 100.0869

Mole ratio SO₂:CaCO₃=1:1

1 tonne = $1×10^6g$

Let m= tonnes of CaCO₃

$\frac{1×10^6}{64.066}=\frac{m×10^6}{100.0869}$

$m= 1.562\>\> tonnes$