Answer to Question #288085 in General Chemistry for dghds

Question

The pollutant sulphur dioxide can removed from the air by reaction with calcium carbonate in the presence of oxygen. What mass of calcium carbonate is needed to remove 1 tonne of sulphur dioxide? 

2CaCO₃ + 2SO₂ + O₂ → 2CaSO₄ + 2CO₂

Answer 1

Molar mass of SO₂ = 64 .066g

Molar mas of CaCO₃ = 100.0869

Mole ratio SO₂:CaCO₃=1:1

1 tonne = $1×10^6g$

Let m= tonnes of CaCO₃

$\frac{1×10^6}{64.066}=\frac{m×10^6}{100.0869}$

$m= 1.562\>\> tonnes$