Question #288065

5.2x10^-3 = [0.046]^2/ N2O4


1
Expert's answer
2022-01-31T20:34:01-0500

[N2O4]=(0.046)25.2×103[N_2O_4]=\frac{(0.046)^2}{5.2×10^{-3}}


=0.406923M=0.406923M





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