Calculate the mass of hydrogen formed when 3 g of aluminum reacts with excess hydrochloric acid according to the balanced equation: 2Al + 6 HCl → 2 AlCl3 + 3 H2
molar masses
Molar mass of Al= 26.982
3/26.982= 0.11mol
Mole ratio Al:H2= 2:3
Molar mass of H2= 2.0014
2.0014×2/3×0.11
= 0.15g
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