Calculate the pH of a solution that is 0.20M with benzoic acid and .18with its salt, sodium benzoate
pH"=" pk"_a" "+log\\frac{[A^-]}{[HA]}"
k"_a=6.5\u00d710^{-5}"
pH"=-log(6.5\u00d710^{-5})+log\\frac{0.18}{0.20}"
"=4.1871-0.04576"
"=4.1413"
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