Question

1. What mass of Al will react with 150g of Fe2O3? 

Answer 1

Balanced equation;

Fe₂O₃ + 2 Al → 2 Fe + Al₂O₃

Moles of Fe₂O₃ in 150g = $\dfrac{Mass}{Molar mass} =\dfrac{150g}{159.69g/mol}$

= 0.957 mol

Mole ratio of Al : Fe₂O₃ is 2:1

Moles of Al =$\dfrac{2}{1}x0.957 mol$ = 1.915 mol

Mass of Al = Moles x RAM

= 1.915mol x 63.546g/mol

= 121.666g