Balanced equation;
Fe2O3 + 2 Al → 2 Fe + Al2O3
Moles of Fe2O3 in 150g = MassMolarmass=150g159.69g/mol\dfrac{Mass}{Molar mass} =\dfrac{150g}{159.69g/mol}MolarmassMass=159.69g/mol150g
= 0.957 mol
Mole ratio of Al : Fe2O3 is 2:1
Moles of Al =21x0.957mol\dfrac{2}{1}x0.957 mol12x0.957mol = 1.915 mol
Mass of Al = Moles x RAM
= 1.915mol x 63.546g/mol
= 121.666g
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