Question

6.854 ×× 103 mol glucose, C6 H12 O6

Answer 1

The mass of $6.854×10^3$ Moles of Glucose $C_6H_{12}O_6$

$=$ Molar mass$×$ number of moles

Molar mass of $C_6H_{12}O_6=180.156g$

$\therefore$ Mass$=180.156×6.854×10^{3}$

$=1.2348×10^6g$

$=1234.8kg$