What is the oxidation and reduction reaction to Sc(s) + Cr2O72−(aq) → Sc(OH)3(s) + Cr(OH)4−(aq)?
Oxidation
Sc(s)→ Sc3++3e−Sc_{(s)}\to\>Sc^{3+}+3e^-Sc(s)→Sc3++3e−
Reduction
Cr2(aq)6++3e−→ Cr3+Cr_{2(aq)}^{6+}+3e^-\to\>Cr^{3+}Cr2(aq)6++3e−→Cr3+
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