HA+H2O⇌A−+H3O+
Initial moles of HA (CH3 COOH)
=0.150×100050=0.0075moles
Moles of NAOH added
=0.150×100020=0.003moles
Moles of HA remaining =0.0075−0.003
=0.0045moles
Ka=[HAaq][Haq+][Aaq−]
1.8×10−5=0.0045[Haq+]×0.003
[Haq+]=2.7×10−5
PH=−log2.7×10−5
=4.5686
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