CH3 COOH + NaOH → CH3 COONa+H2O
Number of moles of CH3 COOH
=0.150×100050=0.0075moles
Number of moles of NaOH
=0.150×100020
0.003moles
Moles of excess acid=0.0075−0.003
=0.0045moles
PH= pka+ log [HA][A−]
=−log1.8×10−5+log0.00450.003
=4.7447−0.1761
=4.586
Comments