Question #286493

a 50 ml sample of .1 mol/L HCIO(aq) is titrated with .2 mol/L KOH(aq). find ph given the following volumes of added base: (Ka= 2.8 x 10-8) a) 0.0 ml b) 10.0 ml c) 25.0 ml d) 30.0 ml. show your work


1
Expert's answer
2022-01-12T07:06:01-0500



CH3_3 COOH ++ NaOH \to CH3_3 COONa+H2O+H_2O



Number of moles of CH3_3 COOH

=0.150×501000=0.0075moles=0.150×\frac{50}{1000}=0.0075\>moles


Number of moles of NaOH

=0.150×201000=0.150×\frac{20}{1000}

0.003moles0.003\>moles



Moles of excess acid=0.00750.003=0.0075-0.003

=0.0045moles=0.0045\>moles



PH== pka+pk_a+ log [A][HA]\frac{[A^-]}{[HA]}

=log1.8×105+log0.0030.0045=-log\>1.8×10^{-5}+log\>\frac{0.003}{0.0045}


=4.74470.1761=4.7447-0.1761


=4.586=4.586








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