Answer to Question #285825 in General Chemistry for sumaiya sheikh

Question

how much ammonia gas can be produced from 200 kg of air?

Answer 1

Molar mass of dry air $=28.9647g/mol$

Volume $\%$ of Nitrogen in dry air $=78.084\%$

Volume ratio$=$ Molar ratio

Moles if Nitrogen in $200kg$ of air $=\frac{78.084}{100}×\frac{200000}{28.9647}=5391.7$ Moles

$N_{2(g)}+3H_{2(g)}\to2NH_{3(g)}$

1 mole of Nitrogen yields 2 moles of Ammonia

$5391.7$ moles yields $5391.7×2=10783.4$ Moles of Ammonia

Molar mass of Ammonia $=17.031g/mol$

Ammonia produced $=\frac{10783.4×17.031}{1000}=183.65kg$