Answer to Question #285820 in General Chemistry for sumaiya sheikh

Question

how much hydrogen is required to produce ammonia form 150 gm nitrogen?

Answer 1

N_2(g) + 3H_2(g) = 2NH_3(g)

1 mole of nitrogen gas combines with 3 mols of hydrogen gas to form 2 mol of a ammonia gas.

1 volume of nitrogen reacts with 3 volumes of hydrogen to produce 2 volumes of ammonia

e.g. what volume of hydrogen reacts with 50 cm³ nitrogen and what volume of ammonia will be formed?

The mole ratio is 1 : 3 =2,

so you multiply equation ratio numbers by 50 giving

50 cm³ nitrogen + 150 cm³ hydrogen (3 x 50) ==> 100 cm³ of ammonia (2 x 50)

These experimental facts are keeping with Gay Lussacs law of combining volumes