Aluminum sulfate Al2(SO4)3
Step one is finding molar mass of individual elements
Al=2\26.982=53.964
S=3\32.065=96.18
O=12\15.9994=191.988
=342.132gmol-1
1mol of Al2(SO4)3=342.132g
3.50 x 10-3of of Al2(SO4)3 =?
Therefore=342.132\ 3.50 x 10-3
=342.132/0.0035
=1.1975grams
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