Question

find the percentage of anhydrous salt and water of hydration in CuSo4 . 5H2O

Answer 1

Molar mass of $CuSO_4.5H_2O= 249.72g/mol$

Molar mass of anhydrous

$CuSO_4= 159.62g/mol$

Percentage by mass of anhydrous

$CuSO_4$

$=\frac{159.62}{249.72}×100\%=63.92\%$

Percentage by mass of water of hydration

$= (100-63.92)\%$

$=36.08\%$