Question

When 225 mL of H₂O at 16⁰C are mixed with 85 mL of water at 87⁰C, what is the final temperature? (Assume that no heat is lost to the surroundings; dH₂O = 1.00 g/mL. C_water = 4.18 J/g. K )

Hint: the heat given by the hot water is received by the cold water.

Answer 1

q=mc∆t

 For water q₁ = q₂

 m₁c∆t₁ = m₂c∆t₂

If the density of water is 1.00 g/mL then m₁= 225 g and m₂ = 85 g 

 225 × (t_f - 16) = 85 × (87 - t_f)

 t_f = 35.4677

Final temperature= 35.4677 degrees celsius.