When 225 mL of H2O at 160C are mixed with 85 mL of water at 870C, what is the final temperature? (Assume that no heat is lost to the surroundings; dH2O = 1.00 g/mL. Cwater = 4.18 J/g. K )
Hint: the heat given by the hot water is received by the cold water.
q=mc∆t
For water q1 = q2
m1c∆t1 = m2c∆t2
If the density of water is 1.00 g/mL then m1= 225 g and m2 = 85 g
225 × (tf - 16) = 85 × (87 - tf)
tf = 35.4677
Final temperature= 35.4677 degrees celsius.
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