A sample of carbon dioxide occupies a volume of 3.50 liters at 125 kPa pressure. What pressure would the gas exert if the volume was decreased to 2.00 liters
Applying Boyle's Law;
P1V1 = P2V2
Since we are given P1 = 125kPa, V1 = 3.5L, and V2 = 2.00L.
We are to find P2
Thus, we can rearrange the equation to make P2 the subject of the formula.
Thus, P2 = P1V1/V2
Substituting for P1, V1, and V2 gives
P2 = 125kPa x 3.50L / 2.00L
= 218.75 kPa
Comments
Leave a comment