1. Balance each of the following equations according to the half-reaction method:
a) Br2(l) + SO2(g) ⟶ Br−(aq) + SO42−(aq) (in acid)
b) Cl2(g) + OH−(aq) ⟶ Cl−(aq) + ClO3−(aq) (in base)
a) Br2(l) + 2e- = 2Br−(aq)
SO2(g) + 2H2O (l) = SO42−(aq) + 4H+ (aq) +2e-
Total: Br2(l) + SO2(g) + 2H2O (l) = 2Br−(aq) + SO42−(aq) + 4H+ (aq)
b) Cl2(g) + 2e- = 2Cl−(aq)
Cl2(g) + 12OH−(aq) = 2ClO3−(aq) + 6H2O (l) + 10e-
Total: 3Cl2(g) + 6OH−(aq) = 5Cl−(aq) + ClO3−(aq) + 3H2O (l)
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