Answer to Question #284231 in General Chemistry for Dairuuo

Question

A precipitation reaction occurs when 50.0 ml of 0.50 M BaBl2 is mixed with 75.0 mL of 0.75 M Na2CO3. The only precipitate is BaCO3 formed.

Write Balanced Equation

Limiting reactant

Theoretical Mass oF BaCO3

Actual Mass of BaCO3

Answer 1

Balanced and Complete Reaction.

Na₂CO₃ + BaCl₂ = BaCO₃ + 2 NaCl .

Milli Moles of BaCl₂ = ( 50 × 0.5 ) = 25

Milli Moles of Na₂CO₃ = ( 75 × 0.75 ) = 56.25

So, BaCl₂ have less amount So, BaCl₂ is limiting reagent .

Mass of BaCl₂ = 25 × 208.23 = 5205.75 mg .

Mass of BaCl₂ = 5.20575 g .

If 100 % yield then 5.20575 g is actual mass

If yield is smaller than then actual mass is smaller than theoritical .