Determine the normal concentration of a solution composed of 53.2 g of pure K3PO4
in 2475 mL of the solution.
Molar mass: 212g/mol
Moles =53.2212=0.25moles=\frac{53.2}{212}=0.25moles=21253.2=0.25moles
Molarity =0.252.475=0.10M=\frac{0.25}{2.475}=0.10M=2.4750.25=0.10M
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments