Question

for copper the variation with temperature for heat capacity at constant pressure is Cp=22.46+(00.628) calculate the change of the molar enthalopy when temperature change from293 to 393

Answer 1

C_p = dH/dT at constant pressure

C_p = ∆H/(T₂ - T₁)

∆H = C_p x (T₂ - T₁) = (22.46+(00.628)) x (393 - 293) = 2308.8 J