A sample of oxygen, O2, occupies 32.2 mL at 30 °C and 452 torr. What volume will it occupy at –70 °C and the same pressure?
V1= 32.2ml
V2 =?
T1= 30°C +273 = 303K
T2 = -70°C +273 =203K
V1T1=V2T2\frac{V1}{T1}= \frac{V2}{T2}T1V1=T2V2
=32.2ml303K=V2203K=\frac{32.2ml}{303K}=\frac{V_2}{203K}=303K32.2ml=203KV2
V2=32.2ml×203K303KV_2=\frac{32.2ml × 203K}{303K}V2=303K32.2ml×203K
V2=21.6mlV_2= 21.6mlV2=21.6ml
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