A sample of nitrogen, N2, occupies 45.0 mL at 27 °C and 600 torr. What pressure will it have if cooled to –73 °C while the volume remains constant?
"V = constant = 45.0 \\;mL \\\\\n\nT_1 = 27+273 = 300 \\;K \\\\\n\np_1 = 600 \\; torr \\\\\n\nT_2 = -73 + 273 = 200 \\;K \\\\\n\n\\frac{p_1}{T_1} = \\frac{p_2}{T_2} \\\\\n\np_2 = \\frac{p_1 T_2}{T_1} \\\\\n\n= \\frac{600 \\times 200}{300} = 400 \\; torr"
Answer: 400 torr
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