To obtain pure lead, lead (II) sulfide is burned in an atmosphere of pure oxygen. The products of the
reaction are lead and sulfur trioxide (SO3). Write a balanced chemical equation for this process. How many
grams of lead will be produced if 2.54 grams of PbS is burned with 1.88 g of O2? Express your answer to
the correct number of significant figures. Be sure to show all steps completed to arrive at the answer.
(Hint: be sure to work the problem with both PbS and O2)
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 239.27 32.00 207.2
2PbS + 3O₂ ⟶ 2Pb + 2SO₃
m/g: 2.54 1.88
2. Calculate the moles of each reactant
3. Calculate the moles of Pb from each reactant
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