Answer to Question #280786 in General Chemistry for mayii

Question

Homes may be heated by pumping hot water through radiators. What mass of  water will provide the same amount of heat when cooled from 95.0 to 35.0 °C, as  the heat provided when 100 g of steam is cooled from 110 °C to 100 °C.  

Answer 1

q = mc∆T. The amount of heat transferred from steam is:

q_steam = 100 g × 1.864 J/(g °C) × (110 – 100) °C = 1864 J

q_water = m_water × 4.184 J/(g °C) × (95 – 35) °C = m_water × 251.04 J/g = q_steam = 1864 J

$m_{water} =\frac{1864J}{251.04J/g} =7.43g$