You have a solution that is composed of 0.235 moles NaCl (58.45 g/mole) and 58.0 g of H2O (d = 0.986 g/mL). What is the molarity of this solution?
d = m/V
V = m/d
V (H2O) = 58.0 g / 0.986 g/mL = 58.8 mL (0.0588 L).
To find the molarity we divide the moles of solute by the volume of the solution expressed in L:
molarity = 0.235 moles NaCl / 0.0588 L = 4.0 M
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