Question

consider this reaction: CI2(g)+F2(g)⇌2CIF(g) K=19.9

1) give its Q expression

2) Solve for Q if the initial concentrations are [CI2]= 0.5M, [F2]= 0.2M, and [CIF]= 7.3M

3) Predict the direction of the reaction given the initial concentration of the substances in the reaction mixture

Answer 1

1)

$Q=\frac{[ClF]^2}{[Cl_2][F_2]}$

2)

$Q=\frac{(7.3\ M)^2}{0.5\ M\times0.2\ M}\approx530$

3)

Since Q > K, there is an excess of products, so the reaction will shift to the left (toward reactants).