Answer to Question #280202 in General Chemistry for Edikandinho

Question

Cal. PH and POH for each of the following solutions at 25°c.

i) 1.0×10^-3 OH-

I) 1.0m H+

Answer 1

pH + pOH = 14

pH = - lg [H⁺]

pOH = - lg [OH^-]

1) pOH = - lg [1.0×10^-3] = 3

pH = 14 - 3 = 11

2) pH = - lg [1.0] = 0