A chemical reaction requires 6.00 moles of Fe(NO3)3. What mass of Iron (III) Nitrate is needed?
The molar mass of Iron (III) Nitrate is 241.86 grams per mole. We use the molar mass as a conversion factor to determine the mass of pure Iron (III) Nitrate.
(6.00 moles)(241.86 grams/1mol)= 1451.16 g
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