Iron metals react with hydrochloric acid ass follows:
2Fe(s) + 6HCl(aq)------- 2FeCl3 (aq) + 3H2(g). If 22.4g of iron reacts with excess HCl, and 59.4g of FeCl3 are collected, what is the percent yield of Al2(SO4)3
22.4/81.8×100= 27.38%
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