Given a fixed amount of gas held at constant pressure, calculate the temperature to which the gas have to be changed if a 1.75 L sample at 23.0 degrees celsius were to have a final volume of 3.5 L
p=constantV1=1.75 LT1=23.0+273=296 KV2=3.5 LV1T1=V2T2T2=T1V2V1T2=296×3.51.75=592 KT2=592−273=319 °Cp=constant \\ V_1 = 1.75 \;L \\ T_1 = 23.0 + 273 = 296 \;K \\ V_2 = 3.5 \;L \\ \frac{V_1}{T_1} = \frac{V_2}{T_2} \\ T_2 = \frac{T_1V_2}{V_1} \\ T_2 = \frac{296 \times 3.5}{1.75} = 592 \;K \\ T_2 = 592 -273 = 319 \; °Cp=constantV1=1.75LT1=23.0+273=296KV2=3.5LT1V1=T2V2T2=V1T1V2T2=1.75296×3.5=592KT2=592−273=319°C
Answer: 319 °C
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