Question

A sample of copper weighing 7.55 kg has undergone heating. Its temperature has risen from 25oC

to 329.8oC. Given a specific heat capacity of 0.385 J/g oC, what is the total heat absorbed by the

metal in kJ?

Answer 1

$\Delta\>H=MC\Delta\>T$

$M=7.55kg$

$C=0.385J/g°c$

$=0 .385kJ/kg°c$

$\Delta\>T=329.8-25$

$=304.8°c$

Heat absorbed $=7.55×0.385×304.8$

$=885.98kJ$