Question

A chemical reaction has an equation as shown:

AB + 2 CD --> 3 E + 1/3 A₃D₆

The following are the ΔfH⁰: (kJ/mol)

AB = 324

E = 24

CD = - 76

A₃D₆ = - 76

Answer 1

$ΔfH⁰=324+24-76-76=196kJ/mol$