A chemical reaction has an equation as shown:
AB + 2 CD --> 3 E + 1/3 A₃D₆
The following are the ΔfH⁰: (kJ/mol)
AB = 324
E = 24
CD = - 76
A₃D₆ = - 76
"\u0394fH\u2070=324+24-76-76=196kJ\/mol"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment