Question #277660

A 7.547 g fuel which has heating value of 33kJ/kg is burned in calorimeter and initially at 25.00 degC. Upon triggering the temperature become 28.50 degC


What is the calorimeter constant in J/K?


1
Expert's answer
2021-12-10T02:23:03-0500

Q=mcdTQ= mcdT

= 7.547× 10^-3 × 33×( 3.50+ 273.15)

= 2.088J/K


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