Answer to Question #277582 in General Chemistry for johny

Question

1. Phosphoric acid can be prepared from phosphorus triiodide according to the reaction:

    Pl₃ (s)  +  H₂O(l) -----------> H₃PO₄(aq) + HI(g)

If 150 g of PI₃ (MM = 411.7 g/mol) is added to 250 mL OF H2O (g/mol), d = 1.00 g/mL), Identify which will be limiting and excess reagents. (10pts) How many grams of H₃PO₄ (MM = 97.99 g/mol) will be produced theoretically?

Answer 1

To get the mass of water

Density= mass/vol

Mass=vol×density

Mass=250g

If 411g of Pb react with 54g of H2O

Then 150g ------------------------- Xg of H2O

X=19.71g

So H2O is the excess reagent and PI is the limiting reagent.

2)If 411.7g of PI3 produce 97.99g of H3PO4

Then 150g will produce Xg of H3PO4

X=35.7g of H3PO4 will be produced.