3.Calculate the volumeoccupied by 5.0 moles of nitrogen gas (N2) at 28°C and 2.05 atm in a disinfectant
aerosol spray.
2. Calculate the number of moles of oxygen(O2) in a 35.0 L ventilator cylinder at STP.
1)P=2.05atm1)\\P=2.05atm1)P=2.05atm
V=V=V=
n=5molesn=5molesn=5moles
R=0.0821.atmLmolKR=0.0821. \frac{atmL}{molK}R=0.0821.molKatmL
T=(28+273)K=301KT=(28+273)K=301KT=(28+273)K=301K
PV=nRT ⟹ V=nRTPPV=nRT\implies\>V=\frac{nRT}{P}PV=nRT⟹V=PnRT
V=5×0.0821×3012.05V=\frac{5×0.0821×301}{2.05}V=2.055×0.0821×301
=60.27L=60.27L=60.27L
2) P=1atmV=35Ln=R=0.0821 atmLmolK2)\\\>P=1atm\\V=35L\\n=\\R=0.0821\>\frac{atmL}{molK}2)P=1atmV=35Ln=R=0.0821molKatmL
T=273T=273T=273
PV=nRT ⟹ n=PVRTPV=nRT\implies\>n=\frac{PV}{RT}PV=nRT⟹n=RTPV
n=1×350.0821×273=1.5616molesn=\frac{1×35}{0.0821×273}\\\\=1.5616molesn=0.0821×2731×35=1.5616moles
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