1. The vapor pressure of benzene is 100.0 mmHg at 26.1°C. Calculate the vapor pressure of a solution containing 24.6 g of camphor (C10H16O) dissolved in 98.5 g of benzene. (Camphor is a low-volatility solid.)
P1= 100
P2= ?
V1= 98.5
V2= 98.5+ 24.6= 123.1
"V1P1= V2P2"
P2= 9850/123.1= 80.02mmHg
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