100cm3 of M sulphuric avid is need to an excess of solid sodium hydrogen trioxocarbonate (IV)
Calculates
1- The mass of sodium tetraoxosulphuric (VI) produce
H2SO4 + 2NaHCO3 → Na2SO4 + 2H2O + 2CO2 (Balanced)
limiting reagent= H2SO4 because it gets used up.
Thus,
1 mole of H2SO4 → 1 mole of Na2SO4
1cm³ of H2SO4 → 1cm³ of Na2SO4
100cm³ of H2SO4 → 100cm³ of Na2SO4
molar mass of H2SO4 = 2 × 1 + 32 + 16 × 4= 98g/mol
molar mass of Na2SO4= 2 × 23 + 32 + 16 × 4= 142g/mol
98g of H2SO4 → 142g of Na2SO4
mass= no of moles × molar mass
mass of Na2SO4 produced= 100 × 142= 14200g.
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