Answer to Question #276168 in General Chemistry for mack

Question

Aqueous hydrobromic acid HBr will react with solid sodium hydroxide NaOHto produce aqueous sodium bromide NaBrand liquid water H2OSuppose 17.0 g of hydrobromic acid is mixed with 16. g of sodium hydroxide. Calculate the minimum mass of hydrobromic acid that could be left over by the chemical reaction. Round your answer to 2

 significant digits.

Answer 1

The equation of the reaction is;

NaOH(aq) + HBr(aq) -----> NaBr(aq) + H2O(l)

Number of moles of NaOH = 5.7 g/40g/mol = 0.14 moles

Number of moles of HBr= 20.2 g/81g/mol = 0.25 moles

Since the reaction is in a 1:1 ratio, NaOH is the limiting reactant.

0.14 moles of NaOH yields 0.14 moles water

Mass of water produced = mass × molar mass

Molar mass of water = 18 g/mol

Mass of water produced = 0.14 moles water × 18 g/mol

= 2.5 g of water.