Answer to Question #276025 in General Chemistry for MichaelOvate

Question #276025

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Expert's answer
2021-12-07T04:02:04-0500

H2SO4 + 2NaOH → Na2SO4 + 2H2O

Mr(NaOH) = 23 + 16 + 1 = 40 g/mol

Mr(Na2SO4) = 23x2 + 32 + 16x4 = 142 g/mol

Number of moles of NaOH = mass ÷ relative formula mass = 20 g ÷ 40 g/mol = 0.5 mol

From the equation, 2 mol of NaOH produce 1 mol of Na2SO4, so 0.5 mol of NaOH will produce 0.25 mol of Na2SO4.

mass of Na2SO4 = moles × relative formula mass = 0.25 mol × 142 g/mol = 35.5 g


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