A 10 g gold at 18.0 °C is placed in contact with 20 g iron at 55.6 °C. Calculate the final
temperature of the metals in contact. Given the specific heat capacity of gold and iron are
0.129 J g―1C―1 and 0.444 J g―1C―1 respectively.
Two q's to 0.
(10.0 Au)(0.129)(Tf-18.0°C) + (20.0g Fe)(0.444)(Tf-55.6°C)=0
(1.29Tf-23.22) + (8.88Tf-502.608) = 0
10.17Tf = 525.828
Temperature final = 51.70°C
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