Calculate the partial pressure (in atm) of Ar in a flask that contains a mixture of mols 1. _____ of Ar and 5.0 mols of Ne in the flask with a total pressure of 2.6 atm.
PAr=XArPTotalXAr=Moles of ArTotalMolesP_{Ar}=\Chi_{Ar}P_{Total}\\\Chi_{Ar}=\frac{Moles\>of\>Ar}{Total Moles}PAr=XArPTotalXAr=TotalMolesMolesofAr =16=\frac{1}{6}=61
P_{Ar}=16×2.6=0.4333 Atm\frac{1}{6}×2.6=0.4333\>Atm61×2.6=0.4333Atm
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