Question

Calculate the partial pressure (in atm) of Ar in a flask that contains a mixture of mols 1. _____ of Ar and 5.0 mols of Ne in the flask with a total pressure of 2.6 atm.

Answer 1

$P_{Ar}=\Chi_{Ar}P_{Total}\\\Chi_{Ar}=\frac{Moles\>of\>Ar}{Total Moles}$ $=\frac{1}{6}$

P_{Ar}=$\frac{1}{6}×2.6=0.4333\>Atm$