Calculate the [H+] of a 0.10 M solution of acetic in 0.25 M sodium acetate.
pH = pKa + log [ CH3COONa] / [ CH3COOH]
= 4.76 + log [0.25]/ [ 0.1]
=5.16
[H+]=10−pH[H^+] = 10^{-pH}[H+]=10−pH
[H+]=10−5.16[H^+] = 10^{-5.16}[H+]=10−5.16
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment