An oxide of chromium is made up of 5.20 g chromium and 5.60 g oxygen. What is the empirical formula of the oxide? (Note: An oxide of nitrogen contains 63.1% oxygen and has a molar mass of 76.0 g/mol.)
5.2/76= 0.068mol
Molar mass of O= 15.99
5.6/15.99= 0.35mol
63.1/100× 0.068= 0.04291
0.068-0.04291= 0.02509
0.39291/0.02509= 16
= CrO16
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