Question #273477

How many mL of 0.750 M CaCl2 contain 2.00 g of CaCl2?


1
Expert's answer
2021-12-01T07:29:02-0500

Molar mass: 110.98 g/mol


Moles =2.00110.98=0.018moles=\frac{2.00}{110.98}=0.018moles


Volume =0.0180.750=0.024litres=24ml=\frac{0.018}{0.750}=0.024litres =24ml



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