Answer to Question #273023 in General Chemistry for tinker

Question #273023

a solution that contains 70g of NaNO3 at 30 degrees celicius in 100 ml H2O

Expert's answer

Molar mass of NaNO3 = 84.9947 g/mol

Moles "=\\frac{70}{84.9947}=0.824moles"

Molarity "= \\frac{0.824}{0.1}=0.0824M"

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