Using the chemical equation: 2 Ca3(PO4)2 + 6SiO2 + 10C -> 6CaSiO3 + P4 + 10CO. Calculate the minimum mass of Ca3(PO4)2 required to produce 69.8 grams of P4.
Molar mass of P4= 124
69.8/124=0.563
Molar mass of Ca3(PO4)2= 310.18
= 310.18×2×0.563=349.203g
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