Question

Calculate the grams of water that must be added to 16.0 grams of sugar in the preparation of a 25.0% sugar solution

Answer 1

$$ %$=\frac{m_{(sugar)}}{m_{(sugar)}+m(H_2O)}×100$

25%$=\frac{16}{16+m(H_2O)}×100$

$m(H_2O)=\frac{16×100}{25}-16=48gram$