Answer to Question #271406 in General Chemistry for Forest Sapphirey

Question

A small hole in the wing of a space shuttle requires a 17.7cm² patch

a.) What is the patch's area in space kilometers?

b.) If the patching material costs NASA USD 3.25/in², what is the cost of the patch?

Answer 1

The patch's area in space kilometers

$1cm = 0.00001km$

$1cm^2 = (0.00001km)^2=10^{-10}km^2$

$17.7cm^2=17.7×10^{-10}km^2=2.07×10^{-9}km^{-2}$

b)

$1cm=0.393701inch$

$1cm^2=0.1550inch^2$

$17.7cm^2=17.7×0.1550inch^2=2.7435inch^2$

Cost of patch $= 2.7435×3.25=8.916$

Hence cost = NASA USD 8.916