Question #271406

A small hole in the wing of a space shuttle requires a 17.7cm² patch



a.) What is the patch's area in space kilometers?



b.) If the patching material costs NASA USD 3.25/in², what is the cost of the patch?

1
Expert's answer
2021-11-30T04:27:01-0500

The patch's area in space kilometers


1cm=0.00001km1cm = 0.00001km

1cm2=(0.00001km)2=1010km21cm^2 = (0.00001km)^2=10^{-10}km^2

17.7cm2=17.7×1010km2=2.07×109km217.7cm^2=17.7×10^{-10}km^2=2.07×10^{-9}km^{-2}



b)

1cm=0.393701inch1cm=0.393701inch

1cm2=0.1550inch21cm^2=0.1550inch^2

17.7cm2=17.7×0.1550inch2=2.7435inch217.7cm^2=17.7×0.1550inch^2=2.7435inch^2

Cost of patch =2.7435×3.25=8.916= 2.7435×3.25=8.916

Hence cost = NASA USD 8.916





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