Question

3.25g of metal x reacted completely with 3.25g of chloride to form the metallic chloride.calculate the empirical formula of the metallic chloride (x=65,cl=35.5).

Answer 1

Solution.

$n(Me) = \frac{3.25}{65} = 0.05 mol$

$n(Cl2) = \frac{3.25}{71} = 0.046 mol$

n(Me):n(Cl2) = 1.08:1 = 1:1

So, formula is MeCl2

Answer:

MeCl2