the reaction between methane and water vapour produces carbon dioxide gas and hydrogen gas in the following reaction: CH4(g)+2H2O(g)=CO2(g)+4H2(g)
you initially add 2.00 mol of methane and 6.00 of water vapour to an 8.00L container. calculate Keq for the forward reaction if the equilibrium concentration of water vapour was measured to be 0.56mol/L
Molar mass of methane=16.04= 2/16.04
= 0.125
Molar mass of H2O= 18
= 6/18= 0.33
= 0.455/8
= 0.0569mol/L
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