Question

calculate the normality of the solution containing the following:5.267gm/L K2Cr2O7(the Cr6+ is reduced to Cr3+)

294.19

Answer 1

Normality(N)= nM

Where n= equivalent in a compound

M= concentration of the compound in moles/ litre

Each Cr atom has 3 reacting units ( electrons)

Two Cr atom has 6 reacting units.

Molarity$= \frac{5.267}{294.19}=0.01790$

Normality$= 6×0.0179=0.1074\,Eq/L$